Django Order_BY custom function

Question

I have field in model roll_numb. Theroll_numb has values as follows.

070-001
070-007
070-343
080-002
080-008

When i order_by roll_numb the sorting is as it is above. I want to split the roll_numb by - and sort by the remainder. (i.e. 001, 002, 008)

Code

class Meta:
        ordering = ['roll_numb']

Answer 1

I think it is not possible to order a queryset by method of model in Django's ORM scope.

So in order to sort your queryset by your custom method, I recommend 2 ways:

First

qs = mymodel.objects.all()
qs = sorted(qs, key: lambda i: i.roll_numb().split('-')[1])

Second

Add another field to your model, so enable Django's ORM to sort by the desired value:

MyModel(models.Model):
    class Meta:
        ordering = ['roll_numb_splitted']

   roll_numb_splitted = models.Charfield(max_length=3)

   def save(self, *args, **kwargs):
        # this is a check to run once
        if not self.pk:
            self.roll_numb_splitted = self.roll_numb().split('-')[1]
        return super(MyModel, self).save(*args, **kwargs)