How to read special characters in a string in java

Question

I'm given a String & I need to find whether it contains any special character or not? I tried using charAt() and ASCII values.But it didn't work.Someone please help.Thanks in advance.

for(int i=0;i<s.length();i++)
{
    char c=s.charAt(i);
    if(65<=c<=90)
    {
        System.out.println("Valid");
    }
    else if(97<=c<=122)
    {
        System.out.println("Invalid as it contains lower case letter");
        break;
    }
    else if(48<=c<=57)
    {
        System.out.println("Invalid as it contains numbers");
        break;
    }
    else
        System.out.println("Invalid as it contains special characters");
}

Answer 1

Something like this would work :

public static void main(String[] args) {
    String s = "asda®††∆˚∆asd121";
    System.out.println(s.replaceAll("[a-zA-Z0-9]", ""));
}

O/P :

®††∆˚∆

If the size after replacing is 0, then there were no special characters. You can update the regex with what you consider as special. :)