I'm using Automapper to copy interfaces to different implementations (for serialization, for view model, for database mapping, etc...).
My code is a lot more complex but I've isolated the problem in the following code snippet sample.
Considering the following code, do I miss something because the second assertion is failing:
[Test]
public void AutoMapperTest()
{
Mapper.CreateMap<IMyBaseInterface, MyClass>();
Mapper.CreateMap<IMyInterface, MyClass>();
IMyBaseInterface baseInstance = new MyBaseClass{ MyBaseProperty = "MyBase" };
var concrete = Mapper.Map<MyClass>(baseInstance);
concrete.MyClassProperty = "MyClass";
MyClass mapped = Mapper.Map<IMyInterface,MyClass>(concrete);
Assert.AreEqual(concrete.MyBaseProperty, mapped.MyBaseProperty);
Assert.AreEqual(concrete.MyClassProperty, mapped.MyClassProperty);
}
Expected: "MyClass" But was: null
public class MyClass : MyBaseClass, IMyInterface
{
public string MyClassProperty { get; set; }
}
public interface IMyInterface : IMyBaseInterface
{
string MyClassProperty { get; }
}
public class MyBaseClass : IMyBaseInterface
{
public string MyBaseProperty { get; set; }
}
public interface IMyBaseInterface
{
string MyBaseProperty { get; }
}
Automapper : 4.1.1.0 / .Net: 4.5 / VS 2013
Work around:
Add Mapper.CreateMap<MyClass, MyClass>();
I don't see the above as a real answer. Since it means that if I have several implementations, I have to create mappings for all combinations. And add another mapping if I write a new implementation, even if the whole time, they all implement the same interface.