For the finite BYTE of Octal numbers

Question

For the finite BYTE of Octal numbers R₈ = {0,1,2,3,4,5,6,7,10,1,..,N}

The number in BYTE R₈: N₈ = (7₈)⁵ MOD (400₈) = ___?______

Can someone please help me answer this. I got 247₈, but I am unsure if this is correct.

Thank you

Answer 1

Yes, the result is correct. 7^5=16807, 400 octal is 256 decimal, 16807 mod 256 = 167 and 167 in octal is 247.

You should have showed your steps like this in the question.