I want to translate following grammar to regex
A -> bcA | dD |aB
B -> aB |a
D -> dD |d
So here string will end either in a's or d's
Regular expression will start with (bc)+
but can anyone explain how can write d+/a+ in regular expression for languages?
It depends on the regex dialect you're using.
In general, a |
within a ()
grouping creates an 'or', for example:
th(er|os)e
... matches 'there' or 'those'.
But check the documentation for your dialect, to check whether brackets have to be escaped, whether '|' is supported, and so on.