I just started learning assembly language and I am already stuck on the part to "display the decimal values stored in a register on the screen". Im using the emu8086, any help would be appreciated! :)
.model small ;Specifies the memory model used for program to identify the size of code and data segments
org 100h ;allocate 100H memory locations for stack
.data ;the segment of the memory to declare/initialze the variables
var1 db 0006
var2 db 0002
var3 db 0001
.code ;start of the code segment
main proc ;start of the first procedure
mov bl, var1
add bl, var2
add bl, var3
mov ah, 00h ; display function here?
mov dl, bl ; output the bl register's value?
int 21h
mov ah, 4ch ;exit DOS function
int 21h
endp ;end of the first procedure
end main ;end of the complete assembly program
ret
mov ah, 00h ; display function here?
No, the single-char display function is at AH=2 / int 21h
Since your BL register contains only a small value (9) all it would have taken was:
mov ah, 02h
mov dl, bl
add dl, "0" ; Integer to single-digit ASCII character
int 21h
If values become a bit bigger but not exceeding 99 you can get by with:
mov al, bl ; [0,99]
aam ; divide by 10: quotient in ah, remainder in al (opposite of DIV)
add ax, "00"
xchg al, ah
mov dx, ax
mov ah, 02h
int 21h
mov dl, dh
int 21h
A solution that doesn't use the AAM instruction:
mov al, bl ; [0,99]
cbw ; Same result as 'mov ah, 0' in this case
mov dl, 10
div dl ; Divides AX by 10: quotient in al, remainder in ah
add ax, "00"
mov dx, ax
mov ah, 02h
int 21h
mov dl, dh
int 21h