I need to find whether a number is divisible by 3 without using %
, /
or *
. The hint given was to use atoi()
function. Any idea how to do it?
Subtract 3 until you either
a) hit 0 - number was divisible by 3
b) get a number less than 0 - number wasn't divisible
-- edited version to fix noted problems
while n > 0:
n -= 3
while n < 0:
n += 3
return n == 0