it should produce something like:
input = [1,2,3,4,5,6]
output = scan_every_other(lambda x:x, input)
// output should be [1,3,5]
I have briefly read the theano.scan tutorial but I didn't find what I'm looking for. Thank you.:)
You don't need to use theano.scan
. Just use ordinary index/slice notation as in numpy:
In numpy, if
input = [1,2,3,4,5,6]
then
print input[::2]
will display
[1, 3, 5]
In Theano, this can be achieved by doing the same thing:
import theano
import theano.tensor as tt
input = tt.vector()
f = theano.function([input], input[::2])
print f([1,2,3,4,5,6])