Behaviour of all() in python

Question

>>all([])
True
>>all([[]])
False
>>all([[[]]])
True
>>all([[[[]]]])
True

The documentation of all() reads that it returns True is all the elements are True/For an empty list. Why does all([ [ ] ]) evaluate to False? Because [ ] is a member of [ [ ] ], it should evaluate to True as well.

Answer 1

>>all([])
True

because all iterables the list are True (there are zero iterables though)

>>all([[]])
False

there is one empty iterable (innermost empty list) which would evaluate to False

>>all([[[]]])
True

the only iterable here ( [[]] ) has one empty list inside of it, and hence evaluates to True

>>all([[[[]]]])
>>True

same as above