I was helping someone over at Ask Ubuntu with , what should of been a simple issue of connecting a Wiimote to Ubuntu, however we ran in to a bug in the driver.
The driver would request a bluetooth pairing code for the device, the user did not have one.
The user found a post on wiibrew explaining how to extract the code with a bit of C code.
They gave
char pin[6];
pin[0] = 0x6D;
pin[1] = 0x7E;
pin[2] = 0x3B;
pin[3] = 0x35;
pin[4] = 0x1E;
pin[5] = 0x00;
So. the user made what they thought was a valid C file
#include <stdio.h>
int main(void)
{
char pin[6];
pin[0] = 0x41;
pin[1] = 0x7D;
pin[2] = 0x5D;
pin[3] = 0x8A;
pin[4] = 0xD2;
pin[5] = 0x40;
printf("the password is:\n"); printf("%s \n", pin );
}
The code compiles fine, no errors, however it should produce a 6 number passcode but just displays what looks like nonsense characters,
A}]��@
As I am not a programmer, I don't understand what is wrong with this output, why did it give this result and how can we get the actual pairing code using this ?
It is printing fine 0x8A and 0xD2 are not valid ASCII characters. Ascii uses Hex values 0x00-0x7F.