Im using the following code from
https://github.com/cthackers/adm-zip/wiki/ADM-ZIP-Introduction
Whant I need is to get a zip file from request(Im using express and I've request and response) and I need to extract(unzip) it to some path(in the example for my local drive) ,where should I put the req and what Im missing here to make it work
fn: function (req, res) {
var admZip = require('adm-zip');
var zip = new admZip();
zip.addLocalFile("C://TestFolder//TestZip");
in the request body im getting the zip file(im using postman and in the body I use the binary and select a zip file)
Please try my snippet code :
For some information, My App structure like this below :
my path --> C:\xampp\htdocs\service
service
|
-- tmp\
|
-- app.js
|
-- index.html
<html>
<body>
<h3>ZIP Upload:</h3>
<form action="/upload_zip" method="POST" enctype="multipart/form-data">
Select zip to upload:
<input type="file" name="zipFile" id="zipFile">
<input type="submit" value="Upload ZIP" name="submit">
</form>
</body>
</html>
Don't forget using enctype="multipart/form-data"
when you post it using postman or something like that...
var express = require("express");
var fs = require("fs");
var AdmZip = require('adm-zip');
var app = express();
var multer = require("multer");
var multer_dest = multer({dest: "./tmp"}).single('zipFile');
app.get("/",function(req,res){
console.log("Show index.html");
res.sendFile(__dirname+"/"+"index.html");
});
app.post("/upload_zip",multer_dest,function(req,res){
console.log(req.file);
var zip = new AdmZip(req.file.path);
zip.extractAllTo("./tmp");
result = {
file:req.file,
message:"File has been extracted"
};
fs.unlink(req.file.path, function (e) {
if (e) throw e;
console.log('successfully deleted '+req.file.path);
});
res.end(JSON.stringify(result));
});
var server = app.listen(8081,function(){
var host = server.address().address;
var port = server.address().port;
console.log("Example App Listening at http://%s:%s",host,port);
})