I can't find a way to label datapoints in stripchart
. Using the text
function, as suggested in this question, breaks down when points are stacked or jittered.
I have numerical data in 4 categories (columns 2-5) and would like to label each datapoint with the initials (column 1).
This is my data and the code I have tried:
initials,total,interest,slides,presentation
CU,1.6,1.7,1.5,1.6
DS,1.6,1.7,1.5,1.7
VA,1.7,1.5,1.5,2.1
MB,2.3,2.0,2.1,2.9
HS,1.2,1.3,1.4,1.0
LS,1.8,1.8,1.5,2.0
stripchart(CTscores[-1], method = "stack", las = 1)
text(CTscores$total + 0.05, 1, labels = CTscores$name, cex = 0.5)
The plot below is the best I managed so far. As you see, the data point labels overlap. In addition, the longest y label is cut off.
Can points be labelled in a strip chart? Or do I have to display this with another command to allow for labeling?
Here's an alternative that allows you to add color to a strip chart in order to identify the initials:
library(ggplot2)
library(reshape2)
library(gtable)
library(gridExtra)
# Gets default ggplot colors
gg_color_hue <- function(n) {
hues = seq(15, 375, length=n+1)
hcl(h=hues, l=65, c=100)[1:n]}
# Transform to long format
CTscores.m = melt(CTscores, id.var="initials")
# Create a vector of colors with keys for the initials
colvals <- gg_color_hue(nrow(CTscores))
names(colvals) <- sort(CTscores$initials)
# This color vector needs to be the same length as the melted dataset
cols <- rep(colvals,ncol(CTscores)-1)
# Create a basic plot that will have a legend with the desired attributes
g1 <- ggplot(CTscores.m, aes(x=variable, y=value, fill=initials)) +
geom_dotplot(color=NA)+theme_bw()+coord_flip()+scale_fill_manual(values=colvals)
# Extract the legend
fill.legend <- gtable_filter(ggplot_gtable(ggplot_build(g1)), "guide-box")
legGrob <- grobTree(fill.legend)
# Create the plot we want without the legend
g2 <- ggplot(CTscores.m, aes(x=variable, y=value)) +
geom_dotplot(binaxis="y", stackdir="up",binwidth=0.03,fill=cols,color=NA) +
theme_bw()+coord_flip()
# Create the plot with the legend
grid.arrange(g2, legGrob, ncol=2, widths=c(10, 1))