I was just messing around and learning about vectors as well as structs, and at one point, I tried outputting the size of a vector in bytes. Here's the code:
#include <iostream>
#include <vector>
struct Foo{
std::vector<int> a;
};
int main()
{
using std::cout; using std::endl;
Foo* f1 = new Foo;
f1->a.push_back(5);
cout << sizeof(f1->a) << endl;
cout << sizeof(f1->a[0]) << endl;
delete[] f1;
}
The output is 24
and 4
.
Obviously the second line printed 4, because that is the size of an int. But why exactly is the other value 24? Does a vector take up 24 bytes of memory? Thanks!
While the public interface of std::vector
is defined by the standard, there can be different implementations: in other words, what's under the hood of std::vector
can change from implementation to implementation.
Even in the same implementation (for example: the STL implementation that comes with a given version of Visual C++), the internals of std::vector
can change from release builds and debug builds.
The 24 size you see can be explained as 3 pointers (each pointer is 8 bytes in size on 64-bit architectures; so you have 3 x 8 = 24 bytes). These pointers can be: