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phpbashshellproc-open

php proc_open file descriptor in bash command

When we use proc_open in PHP:

<?php

$descriptors = array(
    array('pipe', 'r'),
    array('pipe', 'w'),
    array('pipe', 'w'),
);

$cmd = 'cat <(ls)';
//$cmd = 'ls';
echo $cmd . PHP_EOL;
$ph = proc_open($cmd, $descriptors, $pipes);
echo stream_get_contents($pipes[1]);
echo stream_get_contents($pipes[2]);
proc_close($ph);

When run this script, an error occurred:

$ php test.php 
cat <(ls)
sh: 1: Syntax error: "(" unexpected

but run the raw cmd:

$ cat <(ls)
clusterRegions.php
composer.json
composer.lock
cvCells.php
kent
prepareForTF.php
README.txt
scoreRegions.php
test.php
tests
vendor

Seems that the <() thing cannot be recognized by proc_open. So how to pass a bash command with a file descriptor to proc_open ?

Solution

  • @Etan Reisner, you are right, when I change to bash, it runs well.

    $cmd = 'bash -c "cat <(ls)"';