Script to generate random string not working

Question

I'm trying to generate random string with white spaces but it is not working :

/rs {
  %i=1
  %r=$rand(1,50)
  %s=$rand(a,z)
  while(%i <= %r) {
    %i=%i+1
    %s=%s $+ $rand(a,z)
    if(1 == rand(1,4) %s=%s $+ $chr(32)
  }
  echo %s
}

Returns :

WHILE(%I Unknown command

Any ideas ?

Answer 1

You had some issues, those are just few of them.

• Spaces: mSL statements are sensebile when it concerns to spaces, those you should put spaces between the while (expression), if (expression) and even %i = 1 and %r = $rand(1,50) etc'

• Parenthesis: You probably have forgotten the little parenthesis at the space generator condition. Should be if (1 == rand(1,4)) %s=%s $+ $chr(32)

• $ sign: You also forgotten to put this sign before this identifier rand(1,4) should be $rand(1,4)

Fixed Snippet:

rs {
  %i = 1
  %r = $rand(1,50)
  %s = $rand(a,z)
  while (%i <= %r) {
    %i = %i + 1
    %s = %s $+ $rand(a,z)
    if (1 == $rand(1,4)) %s = %s $chr(32)

  }
  echo -ag %s
}

I took the liberty of designing the code a bit different, now you can use it as $identifier instead of an alias, which will give you further flexibility and usability.

Usages:

• echo -ag $rs (default will be 50 characters long)
• echo -ag $rs(20) (random string with length of 20 charcathers)
• set %myName $rs(15) (will save the output random string into a constant variable)

Snippet:

rs {
  if (!$1) {
    tokenize 32 50
  }

  var %randString
  var %randStringLength = $rand(1, $1)
  var %i = 1
  while (%i <= %randStringLength) {
    %randString = %randString $+ $rand(a, z)
    if ($rand(1, 4) == 1) {
      %randString = %randString $chr(32)
    }
    inc %i
  }
  return %randString
}