I have two lists as follows.
count = (1, 0, 0, 2, 0, 0, 1, 1, 1, 2)
bins = [[2.0, 3.0], [3.0, 4.0], [4.0, 5.0], [5.0, 6.0], [6.0, 7.0], [7.0, 8.0], [8.0, 9.0], [9.0, 10.0], [10.0, 11.0], [11.0, 12.0], [12.0]]
I tried to create a dictionary using following;
dictionary = dict(itertools.izip(count, bins))
And it gives me {"0": [7.0, 8.0], "1": [10.0, 11.0], "2": [11.0, 12.0]}
It gives only the unique key values only but I need to get the all the pairs as below.
{"0": [3.0, 4.0],"0": [4.0, 5.0],"0": [6.0, 7.0],"0": [7.0, 8.0], "1": [2.0, 3.0],"1": [8.0, 9.0], "1": [9.0, 10.0], "1": [10.0, 11.0], "2": [6.0, 7.0] ,"2": [11.0, 12.0]}
or interchange of keys and values in the above dictionary is acceptable.(because keys should be unique) How can I do that?
You can't use a list as a key to a dictionary as it is mutable.
You could convert the list to a tuple:
>>> count = (1, 0, 0, 2, 0)
>>> bins = [[2.0, 3.0], [3.0, 4.0], [4.0, 5.0], [5.0, 6.0], [6.0, 7.0], [7.0, 8.0]]
>>> {tuple(key): value for (key, value) in zip(bins, count)}
{(4.0, 5.0): 0,
(3.0, 4.0): 0,
(5.0, 6.0): 2,
(2.0, 3.0): 1,
(6.0, 7.0): 0}
If you want to serialise to json, the keys need to be strings. You could convert the bins to strings instead:
>>> {str(key): value for (key, value) in zip(bins, count)}
{'[2.0, 3.0]': 1, '[4.0, 5.0]': 0, '[6.0, 7.0]': 0, '[5.0, 6.0]': 2, '[3.0, 4.0]': 0}
>>> import json
>>> json.dumps(_)
'{"[2.0, 3.0]": 1, "[4.0, 5.0]": 0, "[6.0, 7.0]": 0, "[5.0, 6.0]": 2, "[3.0, 4.0]": 0}'
Alternatively, just serialise the pairs, and make the dictionary on the receiving end:
>>> zip(bins, count)
[([2.0, 3.0], 1), ([3.0, 4.0], 0), ([4.0, 5.0], 0), ([5.0, 6.0], 2), ([6.0, 7.0], 0)]
>>> import json
>>> json.dumps(_)
'[[[2.0, 3.0], 1], [[3.0, 4.0], 0], [[4.0, 5.0], 0], [[5.0, 6.0], 2], [[6.0, 7.0], 0]]'