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shellfish

How do you change fish pwd length in prompt using fish_prompt_pwd_dir_length?


I want fish shell to show full path in prompt. Looking at source of pwd_prompt I see a variable named fish_prompt_pwd_dir_length, that should do what I want if I set it to 0.

But when I do set -U fish_prompt_pwd_dir_length 0 nothing happens.

Looking in fish_config variables tab I see that this var is set to 0, but still path shown reduced.

What am I doing wrong and can you actually do that without writing your own pwd_prompt function?


Solution

  • UPD (June 20, 2016):

    Since version 2.3.0 (which is now recent) all is working as expected

    Previous answer:

    My workaround so far is to copy prompt_pwd into new function prompt_pwd_full and mess with it a little bit.

    prompt_pwd_full.fish:

    set -l args_pre
    set args_pre $args_pre -e 's|^/private/|/|'
    
    function prompt_pwd_full -V args_pre
      set -q fish_prompt_pwd_dir_length; or set -l fish_prompt_pwd_dir_length 1
    
      if [ $fish_prompt_pwd_dir_length -eq 0 ]
        set -l fish_prompt_pwd_dir_length 99999
      end
    
      set -l realhome ~
      echo $PWD | sed -e "s|^$realhome|~|" $args_pre -e 's-\([^/.]{'"$fish_prompt_pwd_dir_length"'}\)[^/]*/-\1/-g'
    end
    

    note: I am on OS X, so I threw out a bunch of code that wasn’t related to it, so it might not work in other OS’es.

    UPD: As faho noted in the comment, there is no particular reason to rewrite /private/ to /, so my function is looking like this now:

    function prompt_pwd_full
      set -q fish_prompt_pwd_dir_length; or set -l fish_prompt_pwd_dir_length 1
    
      if [ $fish_prompt_pwd_dir_length -eq 0 ]
        set -l fish_prompt_pwd_dir_length 99999
      end
    
      set -l realhome ~
      echo $PWD | sed -e "s|^$realhome|~|" -e 's-\([^/.]{'"$fish_prompt_pwd_dir_length"'}\)[^/]*/-\1/-g'
    end