eval() with a variable operator

Question

I'm Using Python 3.4. I receive the error:

Traceback (most recent call last):
  File "H:/GCSE's/Computing/Assesment/1/School Grading Script.py", line 44, in <module>
    if answer== eval(num1<currentop>num2):
TypeError: unorderable types: int() < str()

when trying to execute this code

operator=["+","-","*"]
num1=random.randint(0,10)
num2=random.randint(0,10)
currentop=random.choice(operator)

answer = input("What is " + str(num1) + str(currentop) + str(num2) + "?\n")
if answer== eval(num1<currentop>num2):
    print("correct")
else:
    print(incorrect)

What I want to do is to check the answer against the randomly generated variables

Answer 1

Using eval is really bad practice, and should be avoided. For what you are trying to do, you should be making use of operator.

Change your data structure to use a dictionary to make it easier on you to perform your operations. Something like this:

import operator

operators = {
    "+": operator.add
} 

num1 = 4
num2 = 5

res = operators.get("+")(num1, num2)

Output of res:

9

To apply your random implementation in to this, you make use of the dictionaries keys() to do a random.choice on that:

random.choice(list(operators.keys()))

---

Simple example applying random:

import operator
import random

operators = {
    "+": operator.add,
    "-": operator.sub,
    "*": operator.mul
}

num1 = 4
num2 = 5

res = operators.get(random.choice(list(operators.keys())))(num1, num2)