I have a template class receiving multiple types, each type received is subclass of one of two options. I want to expand them differently depending the parent class identifying each of them. This is equivalent to implement "filter" over the variadic template parameters.
For example:
class A{};
class B{};
template<class... C>
struct F{
std::tuple<types_derived_by<A, C>...> fn(types_subclassing<B, C>...){}
};
The types_derived_by template function should produce a variadic template pack with all the types in C that are derived from A, or B.
For example:
struct DA : public A{};
struct DB : public B{};
int main(){
F<DA, DB> f;
//f has a member function: DA fn(DB);
}
I'm using C++11, but I'm ok to move to c++14 if necessary.
You may do something like:
template <template <typename> class Pred, typename TUPLE, typename Res = std::tuple<>>
struct Filter;
template <template <typename> class Pred, typename Res>
struct Filter<Pred, std::tuple<>, Res>
{
using type = Res;
};
template <template <typename> class Pred, typename T, typename ... Ts, typename ... TRes>
struct Filter<Pred, std::tuple<T, Ts...>, std::tuple<TRes...>> :
Filter<Pred,
std::tuple<Ts...>,
std::conditional_t<Pred<T>::value,
std::tuple<TRes..., T>,
std::tuple<TRes...>>>
{
};
or alternatively, using std::tuple_cat
template <template <typename> class Pred, typename TUPLE>
struct Filter;
template <template <typename> class Pred, typename ... Ts>
struct Filter<Pred, std::tuple<Ts...>>
{
using type = decltype(std::tuple_cat(
std::declval<std::conditional_t<Pred<Ts>::value,
std::tuple<Ts>,
std::tuple<>>>()...));
};
and then:
class A {};
template <typename T>
using is_base_of_A = std::is_base_of<A, T>;
class B {};
struct DA : public A{};
struct DB : public B{};
struct DA1 : public A{};
static_assert(std::is_same<std::tuple<DA, DA1>,
Filter<is_base_of_A, std::tuple<DA, DB, DA1>>::type>::value,
"unexpected");