Python 3.5 async for blocks the ioloop

Question

I have a simple aiohttp-server with two handlers. First one does some computations in the async for loop. Second one just returns text response. not_so_long_operation returns 30-th fibonacci number with the slowest recursive implementation, which takes something about one second.

def not_so_long_operation():
    return fib(30)

class arange:
    def __init__(self, n):
        self.n = n
        self.i = 0

    async def __aiter__(self):
        return self

    async def __anext__(self):
        i = self.i
        self.i += 1
        if self.i <= self.n:
            return i
        else:
            raise StopAsyncIteration

# GET /
async def index(request):
    print('request!')
    l = []
    async for i in arange(20):
        print(i)
        l.append(not_so_long_operation())

    return aiohttp.web.Response(text='%d\n' % l[0])

# GET /lol/
async def lol(request):
    print('request!')
    return aiohttp.web.Response(text='just respond\n')

When I'm trying to fetch / and then /lol/, it gives me response for the second one only when the first one gets finished.
What am I doing wrong and how to make index handler release the ioloop on each iteration?

Answer 1

Your example has no yield points (await statements) for switching between tasks. Asynchronous iterator allows to use await inside __aiter__/__anext__ but don't insert it automatically into your code.

Say,

class arange:
    def __init__(self, n):
        self.n = n
        self.i = 0

    async def __aiter__(self):
        return self

    async def __anext__(self):
        i = self.i
        self.i += 1
        if self.i <= self.n:
            await asyncio.sleep(0)  # insert yield point
            return i
        else:
            raise StopAsyncIteration

should work as you expected.

In real application most likely you don't need await asyncio.sleep(0) calls because you will wait on database access and similar activities.