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batch-filesubstr

How to get path of file with batch

I have a batch file that is stored in the c:\data\profile\script.bat directory. My script.dat contains :

@echo off
echo %~dp0%
pause

If I run it, will display on the screen c:\data\profile\. but that's not what I want. I want to display on the screen c:\data\. for that, I have change my batch contains to :

@echo off
echo %~dp0:~0,8%
pause

then I run the file , but the screen only displays c:\data\profile\:~0,8. please let me know how to do it?

Solution

  • How about this:

    @ECHO OFF
PUSHD
CD ..
ECHO %CD%
POPD
PAUSE

    Your code will work if you modify it like this:

    @echo off
set tempPath=%~dp0
echo %tempPath:~0,8%
pause