I'm building a simple Flask
application and I want to return redirect response. Also, I want to maintain total control over headers.
This is what I've got so far:
from flask import Flask
from werkzeug.wrappers import Response
app = Flask(__name__)
@app.route('/toexample')
def to_example():
headers = {
'User-Agent': 'Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:39.0) Gecko/20100101 Firefox/39.0',
'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8',
'Accept-Language': 'en-US,en;q=0.5',
'Accept-Encoding': 'gzip, deflate',
}
return Response('www.example.com', status_code=302, headers=headers)
if __name__ == '__main__':
app.run(debug=True)
I get an error:
TypeError: __init__() got an unexpected keyword argument 'status_code'
Ok, it looks like status_code
doesn't exist on __init__()
, but what is the right way of doing this?
What I ultimately want is a link that a user would click but again, I want to maintain control over headers(Connection, Cookies, Referer, etc.)
I had to add Location
to headers. Also, status_code
is wrong, it should've been status=302
.
Working example:
from flask import Flask
from werkzeug.wrappers import Response
app = Flask(__name__)
@app.route('/toexample')
def to_example():
headers = {
'User-Agent': 'Mozilla/5.0 (X11; Ubuntu; Linux x86_64; rv:39.0) Gecko/20100101 Firefox/39.0',
'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8',
'Accept-Language': 'en-US,en;q=0.5',
'Accept-Encoding': 'gzip, deflate',
'Location': 'http://www.example.com'
}
return Response('http://www.example.com', status=302, headers=headers)
if __name__ == '__main__':
app.run(debug=True)