While looping a range of integers, convert integer representing number of months to the number of years and months

Question

I am using a for loop to display numbers 1-60:

for ($i = 0; $i <= 60; $i++)

within the loop, i want to be able to show the number of years and months. for example:

1 month
2 months
3 month
...
1 year
1 year 1 month
1 year 2 month

and so on...

I tried this:

if (!is_float($i / 12)) {
    $years = $i/12;
} else {
    $years = 'no';
}

This shows 1 on the 12 month, 2 on 24 months but not the in between.

Answer 1

I have used the following solution to complete my code with help from @scaisEdge

for($i=0; $i<=60; $i++) {
    if(!is_float($i/12)) {
        $years = floor($i / 12).' Year';
        $years = $years.($years > 1 ? 's' : '');
        if($years == 0) {
            $years = '';
        }
    }
    $months = ' '.($i % 12).' Month';
    if($months == 0 or $months > 1) {
        $months = $months.'s';
    }

    $display = $years.''.$months;
    echo '<option value="'.$i.'"';
    if($result["warrenty"] == $i) {
        echo 'selected="selected"';
    }
    echo '>'.$display.'</option>';
}