How to represent the kinetic equation in syntax

Question

So i'd like to write the formula

KE = 1 / 2mv^2

in C++, creating a function that calculates a value using the kinetic energy equation. But I'm not entirely sure how to go about showing 1 / 2. Wouldn't I have to make it a double because if I represent 1 / 2 as an integer it'll just display 5? What the compiler is really seeing would be 0.5, from which the zero is cut off? Here is the piece of code I have so far to calculating this equation: double KE = 1/2*mvpow(KE,2); Here's my code and what i'm trying to do.

It's giving me 0 instead of 25 when I use the test values of 2 and 5.

//my protyped function kineticEnergy
double kineticEnergy(int m, int v);

    int main(){
      int m; // needed to pass a value into kineticEnergy function
      int v; // needed to pass a value into kineticEnergy function

      cout << "Enter the mass " << endl;
      cin >> m;
      cout << "Enter the velocity" << endl;
      cin >> v;
      int results = kineticEnergy(m,v);

      cout << "The total kinetic energy of the object is " << results << endl;

      return 0;
    } // end of main

    // ##########################################################
    //
    //  Function name: kineticEnergy
    //
    //  Description:This will grab input from a program and calculate
    // kinetic energy within the function
    // ##########################################################

    double kineticEnergy(int m, int v){
      double KE = 1/2*m*v*pow(KE,2); // equation for calculating kinetic energy

        return KE;
    } // end of kinetic energy

Answer 1

Yes, 1 and 2 are integer constants, so 1/2 gives you 0, which is the result of the integral division of 1 by 2.

What you want is this (assuming "m*v*pow(KE,2)" is correct):

double KE = 1.0/2.0*m*v*pow(KE,2);