So given a multiindexed dataframe, I would like to return only rows that satisfy a condition for all levels of the lower index in a multi index. Here is a small working example:
df = pd.DataFrame({'a': [1, 1, 2, 2], 'b': [1, 2, 3, 4], 'c': [0, 2, 2, 2]})
df = df.set_index(['a', 'b'])
print(df)
out:
c
a b
1 1 0
2 2
2 3 2
4 2
Now, I would like to return the entries for which c > 1
. For instance, I would like to do something like
df[df[c > 1]]
out:
c
a b
1 2 2
2 3 2
4 2
But I want to get
out:
c
a b
2 3 2
4 2
Any thoughts on how to do this in the most efficient way?
I ended up using groupby
:
df.groupby(level=0).filter(lambda x: all([c > 1 for v in x['c']]))