Syntax error with quotes in PHP (mouseover and image source)

Question

I'm trying to include the onmouseover function with an image using this.src='url' in a PHP array.

I don't know if there is another way to call the image source without using single quotes, because it closes the HTML in that line.

$botons = array(
    array(
            'dia'=>1,
            'item'=>'<a href="#"><img src="/img/formula.png" onmouseover="this.src='/img/formula_over.png';" onmouseout="this.src='/img/formula.png';"></a>'
        ),
    );

I think I've tried everything... Any ideas? Thank you.

Answer 1

You just need to ensure you escape the single quotes using backslashes:

$botons = array(
    array(
            'dia'=>1,
            'item'=>'<a href="#"><img src="/img/formula.png" onmouseover="this.src=\'/img/formula_over.png\';" onmouseout="this.src=\'/img/formula.png\';"></a>'
        ),
    );

Hope this helps!