According to De Morgan law:
¬(P ˄ Q) ↔ (¬P) ˅ (¬Q)
¬(P ˅ Q) ↔ (¬P) ˄ (¬Q)
In Python 3.5 when I run:
A = True
B = True
x = not(A and B)==(not A) or (not B)
y = not(A or B)==(not A) and (not B)
print('x is :', x, '\ny is :' ,y)
This returns:
x is : True
y is : False
Question: why y is False?
Try adding some parentheses -- ==
is higher precedence than or
.
Here is the precedence table