Setting hyperjaxb mapping to force implementation of external interface

Question

I have an hyperjaxb xsd file and binding configuration. How can I force my generated classes to implement a custom interface declared in another artifact? I know I can make them extend another class by using

    <xjc:superClass name="com.sample.jpa.entities.BaseEntity"/>

But I need them to implement another interface also. How can I achieve that?

Answer 1

Disclaimer: Author of Hyperjaxb and JAXB2-Basics here.

You can use the Inheritance plugin from JAXB2-Basics together with Hyperjaxb. You can both extend a class or implement an interface. The plugin can also process generics so you can even do stuff like <inheritance:implements>com.acme.foo.MyInterface&lt;com.acme.foo.SomeClass&gt;</inheritance:implements>.

Short guide:

• Enable th plugin via <arg>-Xinheritance</arg> in your pom.xml. Something like:

      <plugin>
          <groupId>org.jvnet.hyperjaxb3</groupId>
          <artifactId>maven-hyperjaxb3-plugin</artifactId>
          <configuration>
              <!--result>mappingFiles</result-->
              <roundtripTestClassName>org.jvnet.hyperjaxb3.ejb.tests.cuone.RoundtripTest</roundtripTestClassName>
              <args>
                  <arg>-Xinheritance</arg>
              </args>
          </configuration>
      </plugin>  
  

  JAXB2-Basics is a dependency if Hyperjaxb so you most probably won't need to do anything else here. See the example (for the annotate plugin but that does not matter).

• Customize your complex types with inheritance:extends or inheritance:implements customization elements. Example:

  <jaxb:bindings schemaLocation="schema.xsd" node="/xsd:schema">
      <jaxb:bindings node="xsd:complexType[@name='WillBeMadeCloneableType']">
          <inheritance:implements>java.lang.Cloneable</inheritance:implements>
      </jaxb:bindings>
  </jaxb:bindings>
  

That should be it.