I'm using a C library from Go using Cgo, and all is good except for callbacks. The library has a callback setter, which takes a pointer to the callback function. The callback function is written in Go and exported using Cgo syntax.
Problem: I can make and export function with char *
argument, but can't with const char *
.
Code to illustrate:
test.go:
package main
/*
typedef void (*cb_func)(const char *, int);
void callback(cb_func);
void myFunc(const char *, int);
*/
import "C"
import (
"fmt"
"unsafe"
)
//export myFunc
func myFunc(buf *C.char, ln C.int) {
fmt.Printf("Got: %s\n", C.GoStringN(buf, ln))
}
func main() {
C.callback((C.cb_func)(unsafe.Pointer(C.myFunc)))
}
test.c:
typedef void (*cb_func)(const char *, int);
void callback(cb_func cb) {
cb("test", 4);
}
Output from go build
:
In file included from $WORK/test/_obj/_cgo_export.c:2:0:
./test.go:54:13: error: conflicting types for 'myFunc'
./test.go:7:6: note: previous declaration of 'myFunc' was here
void myFunc(const char *, int);
^
/tmp/go-build994908053/test/_obj/_cgo_export.c:9:6: error: conflicting types for 'myFunc'
void myFunc(char* p0, int p1)
^
In file included from $WORK/test/_obj/_cgo_export.c:2:0:
./test.go:7:6: note: previous declaration of 'myFunc' was here
void myFunc(const char *, int);
^
Without the const
qualifiers, the code compiles and works as expected.
What can be used instead of *C.char
to get a const string in C?
Since Go does not have const
modifiers for pointers there is no way to translate this behaviour from inside Go code. cgo will always generate headers that do not have the const
modifier. This is also the reason why your code does not build correctly: cgo
creates myFunc
only based on what it knows: buf
should be char*
, not const char*
.
The best way to handle this is to use wrapper on the C side that casts that parameter to const char*
. In your case it is enough to change the definition of myFunc
to void myFunc(char*, int)
. Passing the function to cb_func
will work regardless since casting myFunc
to (*cb_func)(const char*,int)
only adds type information but does not change the memory layout.