Premise 1: p ∧ q
Premise 2: q → r
Premise 3: s → ¬r
Premise 4: ¬r → ¬u
Premise 5: t ∨ s
Premise 6: t → ¬p ∨ U
Prove: u ∧ q
Does anybody know how to solve this proof using rules of inference? I know the rules of inference like modus ponens/tollens but I am not sure how to use them here. I am still beginning to learn these types of proofs.
Can anybody show me how to complete this? Thanks.
Since p ∧ q → p
and p ∧ q → q
, by Premise 1 both p
and q
are true.
By Premise 2 we now know that r
is true.
By Premise 3, r → ¬s
, so s
is false.
Then, by Premise 5, t
must be true.
Now, by Premise 6, ¬p ∨ u
is true, but since p
is true, it is u
which must be true.
Finally, both q
and u
are true and so it is u ∧ q
.
(Also note that Premise 4 is not needed)