According to precedence Postfix increment has higher precendence than <= why i get Output as 5

Question

According to precedence Postfix increment has higher precendence than <=
so when i run this program why do i get Output as 5?

Example
Instead it Should execute as
When a=1
Check While condition 1++<=1
Check While condition 2++<=2
and then printf should print 3

#include <stdio.h>

int main()
{
    int a=1;
    while(a++<=1)
    while(a++<=2);
    printf("%d",a);
    return 0;
}

Answer 1

This is more to do with the semantics of the postfix operator++ than precedence.

1) Check outer while condition 1++<=1. The LHS evaluates to 1, so we move into the inner while. a is incremented to 2.

2) Check inner while condition 2++<=2. The LHS evaluates to 2, the condition is satisfied. a incremented to 3.

3) Check inner while condition 3++<=2. The LHS evaluates to 3, the condition is not satisfied, a is incremented to 4. We move back to the outer loop.

4) Check outer loop condition 4++ <= 1. This fails, the loops end, and a is incremented to 5.