When using the following CSS style, an image covers a div completely, while preserve its proportions:
div {
background: url(images/plants/flower.jpg);
background-size: cover;
background-repeat: no-repeat;
}
The problem is that I need to generate the image URL using PHP and therefore I can't specify it in the CSS property.
I prefer not to use jQuery, JavaScript or inline CSS. The code I am after looks like this:
PHP
$img_url = get_img_url();
echo '<div><img src="' . $img_url . '"></div>';
CSS
div {
width: 600px;
height: 200px;
}
img {
size: cover;
}
I ended up doing the following, without altering the html nor using other language:
PHP
$img_url = get_img_url();
HTML
<div>
<img src="<?php echo $img_url; ?>">
</div>
CSS
div {
width: 600px;
height: 200px;
}
div img {
min-width: 100%;
min-height: 100%;
}