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mathlogarithm

Interpretation of logn^logn?


How should I interpret

How do I interpret this? One way is to take it as logn(logn) and other is . Both would be giving different answers.

For eg: Taking base 2 and n=1024, in first case we get 10*10 as ans. In the second case, we get 10^10 as ans or am I doing something wrong?


Solution

  • Because log(n^log n)=(log n)^2, I would assume that log n^log n should be interpreted as (log n)^(log n). Otherwise, there's no point in the exponentiation. But whoever wrote that down for you should have clarified.