requirejs optimizer just define module name only

Question

I want to use requirejs optimizer just to create/define the module name for my js file.

eg : if i have a file say test.js under modules/moduleA

modules
|
|
-----moduleA
     |
     -----test.js

i want requirejs optimizer to create just the module name for me based on path...eg below I want requirejs optimizer to create the module name modules/moduleA/test and put inside the define present in the test.js

Eg: Before running requireJS optimizer

test.js content:

define( ["my/cart", "my/inventory"],
            function(cart, inventory) {
               ...
           }
        );

After running requirejs optimizer

test.js content

define("modules/moduleA/test",
            ["my/cart", "my/inventory"],
            function(cart, inventory) {
               ...
           }
        );

I Will take care of combining the related dependent files later by means of grunt ...but i want requirejs optimizer to visit each file and give me the module name based on path it presents.

Is this feasible?

Answer 1

James Burke the author of Requirejs provided an answer to this via another forum.

We can easily do this via using transform from RequireJS:

var requirejs = require('requirejs');
requirejs.tools.useLib(function(require) {
  require(['transform'], function (transform) {
     //todo: generate a files array with the list of files to concatenate.

      files.forEach(function(filePath) {
        var fullPath = path.join(targetDir, filePath);
        var contents = fs.readFileSync(fullPath, 'utf8');
        var moduleId = /* todo, figure out what the moduleId is for the module */
        var transformed = transform
                          .toTransport('', moduleId, fullPath, contents);

        //todo: concat the contents together
      });
    });
  });
});