Is there a (fast) way in lua to sort an array and also get the ordering, e.g.
a = {4,3.2,1,7}
=> ordering would be 3,2,1,4 (because a[3]=1, a[2]=3.2, ...)
Try the code below. It sorts an array of indices using the values for comparison.
a = {4,3.2,1,7}
o = {}
for i=1,#a do
o[i]=i
end
table.sort(o,function (x,y) return a[x]<a[y] end)
for i=1,#o do
print(i,o[i],a[o[i]])
end