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iphonensurlconnectionnsurlrequest

Get content of webservice

I've got an URL like here. When I type that into Safari's address bar I see an result like "Error" or "OK".

So, how do I properly call that URL from within my code and get that result as a string?

I've tried it with NSURLConnection, NSURLRequest and NSURLResponse but my response object is always nil.

Solution

  • The "response" in those classes refers to the protocol response (HTTP headers, etc.), not the content.

    To get the content, you have a few options:

    1. Use NSURLConnection in asynchronous mode: Using NSURLConnection

    2. Use NSURLConnection in synchronous mode:

      // Error checks omitted
NSURL *URL = [NSURL URLwithString:@"http://www.myserver.com/myservice.php?param=foobar"];
NSURLRequest *request = [NSURLRequest requestWithURL:URL];
NSData *data = [NSURLConnection sendSynchronousRequest:request
                                     returningResponse:nil
                                                 error:nil];

    3. Use [NSString stringWithContentsOfURL:]

      NSURL *URL = [NSURL URLwithString:@"http://www.myserver.com/myservice.php?param=foobar"];
NSString *content = [NSString stringWithContentsOfURL:URL];

    Of course, you should use options 2 and 3 only if your content will be really small in size, to maintain responsiveness.