I want to export datatable to xlsx directly to my disk instead of giving destination path and saving file on server.
I have following function :
private void ExportToCSVFileOpenXML(DataTable dt, string destination)
{
DataSet ds = new DataSet();
DataTable dtCopy = new DataTable();
dtCopy = dt.Copy();
ds.Tables.Add(dtCopy);
try
{
var workbook = SpreadsheetDocument.Create(Server.MapPath("~/" + destination.Replace("/","").Replace(":","")), DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook);
{
var workbookPart = workbook.AddWorkbookPart();
workbook.WorkbookPart.Workbook = new DocumentFormat.OpenXml.Spreadsheet.Workbook();
workbook.WorkbookPart.Workbook.Sheets = new DocumentFormat.OpenXml.Spreadsheet.Sheets();
foreach (System.Data.DataTable table in ds.Tables)
{
var sheetPart = workbook.WorkbookPart.AddNewPart<WorksheetPart>();
var sheetData = new DocumentFormat.OpenXml.Spreadsheet.SheetData();
sheetPart.Worksheet = new DocumentFormat.OpenXml.Spreadsheet.Worksheet(sheetData);
DocumentFormat.OpenXml.Spreadsheet.Sheets sheets = workbook.WorkbookPart.Workbook.GetFirstChild<DocumentFormat.OpenXml.Spreadsheet.Sheets>();
string relationshipId = workbook.WorkbookPart.GetIdOfPart(sheetPart);
uint sheetId = 1;
if (sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Count() > 0)
{
sheetId =
sheets.Elements<DocumentFormat.OpenXml.Spreadsheet.Sheet>().Select(s => s.SheetId.Value).Max() + 1;
}
DocumentFormat.OpenXml.Spreadsheet.Sheet sheet = new DocumentFormat.OpenXml.Spreadsheet.Sheet() { Id = relationshipId, SheetId = sheetId, Name = table.TableName };
sheets.Append(sheet);
DocumentFormat.OpenXml.Spreadsheet.Row headerRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
List<String> columns = new List<string>();
foreach (System.Data.DataColumn column in table.Columns)
{
columns.Add(column.ColumnName);
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(column.ColumnName);
headerRow.AppendChild(cell);
}
sheetData.AppendChild(headerRow);
foreach (System.Data.DataRow dsrow in table.Rows)
{
DocumentFormat.OpenXml.Spreadsheet.Row newRow = new DocumentFormat.OpenXml.Spreadsheet.Row();
foreach (String col in columns)
{
DocumentFormat.OpenXml.Spreadsheet.Cell cell = new DocumentFormat.OpenXml.Spreadsheet.Cell();
cell.DataType = DocumentFormat.OpenXml.Spreadsheet.CellValues.String;
cell.CellValue = new DocumentFormat.OpenXml.Spreadsheet.CellValue(dsrow[col].ToString()); //
newRow.AppendChild(cell);
}
sheetData.AppendChild(newRow);
}
}
}
}
catch (Exception)
{
throw;
}
}
How can I directly export this to disk instead of saving on server by giving destination path as :
var workbook = SpreadsheetDocument.Create(Server.MapPath("~/" + destination.Replace("/","").Replace(":","")), DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook);
Please help me.
SpreadsheetDocument.Create accepts a stream, string, or package as its first argument so we can just use a MemoryStream to create the workbook in memory and return a byte array.
It should be something like this:
public byte[] ExportToCSVFileOpenXML(DataTable dt)
{
byte[] returnBytes = null;
using (MemoryStream mem = new MemoryStream())
{
var workbook = SpreadsheetDocument.Create(mem, DocumentFormat.OpenXml.SpreadsheetDocumentType.Workbook);
// your code
workbook.WorkbookPart.Workbook.Save();
workbook.Close();
returnBytes = mem.ToArray();
}
return returnBytes;
}
Once you have a byte array passing it as a file should be quite easy.
If you are using MVC it should be something like this in your controler:
return File(ExportToCSVFileOpenXML(aTable), "application/vnd.openxmlformats-officedocument.spreadsheetml.sheet", "export.xlsx");