PHPQuery Select all values from dropdown

Question

I need to get all the values of a dropdown in an array based upon the id of the dropdown using PHPQuery.

The following is the HTML:

<select name="semester" id="semester" class="inputtxt" onChange="javascript:selectSemester(this, this.form);">
    <option value="">-- Select your Semester --</option>
    <option value="2nd" selected>2nd</option>
    <option value="4th" >4th</option>
    <option value="6th" >6th</option>
    <option value="8th" >8th</option>
    <option value="SE1" >SE1</option>
    <option value="SE3" >SE3</option>
    <option value="SE5" >SE5</option>
    <option value="SE7" >SE7</option>
</select>

I tried this:

$semesters = $all['#semester'];

foreach ($semesters as $semester) {
    echo pq($semester)->text();
    echo '<br>';
}

But I get only a single output with all the values concatenated. How do I get each value as separate element in an array?

Answer 1

This code works fine for me:

// include part...

$ids = array();

$raw = file_get_contents("http://localhost:8000/test.html"); // your url

$doc = phpQuery::newDocument($raw);

phpQuery::selectDocument($doc);

/** @var DOMElement $opt */
foreach (pq('#semester > option') as $opt) {
    $ids[] = ($opt->getAttribute('value'));
}

print_r($ids); // check if the array has the values stored

So result is

Array
(
    [0] => 
    [1] => 2nd
    [2] => 4th
    [3] => 6th
    [4] => 8th
    [5] => SE1
    [6] => SE3
    [7] => SE5
    [8] => SE7
)

BTW, you can use $doc['#semester > option'] instead of pq('#semester > option'), both variants works fine. If you need to omit some option - you'd make filter based on option attributes, like if ($opt->getAttribute('value') != "").