How to extract a field from a string with bash

Question

I have an output from a script which looks like this

[{"fileName":"animated.avi","movieId":"34802240145","url":"http://vu.mycdn.me/upload.do?sig=2223a95d7e51832a09d03aa2f23ad3dec0a2c430\u0026expires=1441573849826\u0026clientType=0\u0026id=34802240145\u0026userId=569513266321","accessRights":0}]

I need to extract the value of "url".

I tried using sed like this. Suppose the output is in temp.txt

sed  '/url/,/accessRights/p' temp.txt

Also tried using grep, but was unable to extract it.

Answer 1

How about using cut?

cat temp.txt | cut -d ',' -f3 | cut -d '"' -f4

The fist cut results in

"url":"http://vu.mycdn.me/upload.do?sig=2223a95d7e51832a09d03aa2f23ad3dec0a2c430\u0026expires=1441573849826\u0026clientType=0\u0026id=34802240145\u0026userId=569513266321"

The second one extracts the contents between '"' characters.

Result:

http://vu.mycdn.me/upload.do?sig=2223a95d7e51832a09d03aa2f23ad3dec0a2c430\u0026expires=1441573849826\u0026clientType=0\u0026id=34802240145\u0026userId=569513266321