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rtime-seriesaveragemean

"circular" mean in R


Given a dataset of months, how do I calculate the "average" month, taking into account that months are circular?

months = c(1,1,1,2,3,5,7,9,11,12,12,12)
mean(months)
## [1] 6.333333

In this dummy example, the mean should be in January or December. I see that there are packages for circular statistics, but I'm not sure whether they suit my needs here.


Solution

  • I think

    months <- c(1,1,1,2,3,5,7,9,11,12,12,12)
    library("CircStats")
    

    Now convert from months to radians, compute the circular mean, and convert back to months. I'm subtracting 1 here assuming that January is at "0 radians"/12 o'clock ...

    conv <- 2*pi/12 ## months -> radians
    (res1 <- circ.mean(conv*(months-1))/conv)
    

    The result is -0.3457. You might want:

    (res1 + 12) %% 12
    

    which gives 11.65, i.e. partway through December (since we are still on the 0=January, 11=December scale)

    I think this is right but haven't checked it too carefully.

    For what it's worth, the CircStats::circ.mean function is very simple -- it might not be worth the overhead of loading the package if this is all you need:

    function (x) 
    {
        sinr <- sum(sin(x))
        cosr <- sum(cos(x))
        circmean <- atan2(sinr, cosr)
        circmean
    }
    

    Incorporating @A.Webb's clever alternative from the comments:

     m <- mean(exp(conv*(months-1)*1i))
     12+Arg(m)/conv%%12  ## 'direction', i.e. average month
     Mod(m)              ## 'intensity'