Check if a string is a base36 id?

Question

Assuming I have a function base36-2check,

And a user can input a string, how would I check that that string is base36?

Answer 1

Catch the int constructor's exception, like so:

In [3]: try:
   ...:     int('abc!d', 36)
   ...: except ValueError:
   ...:     print "Nope"

Sample program:

def base36_check(s):
    try:
        int(s, 36)
        return True
    except ValueError:
        return False


print base36_check('abcdefg')
print base36_check('abc!efg')