The more I try to understand this perplexed enigma the more I want to give up.
char *s = "char *s = %c%s%c; main(){printf(s,34,s,34);}"; main(){printf(s,34,s,34);}
How is happening for this one-line source code to generate exactly the same output when the program executes and is there any common notion for this kind of programs?
This is called a Quine.
So let's see what main()
does:
printf(s,34,s,34);
34 is the ASCII code for the character "
(double quote), so this is the same as:
printf(s, '"', s, '"');
The first argument to printf(3)
is the format string. The string passed is:
"char *s = %c%s%c; main(){printf(s,34,s,34);}"
So, printf(3)
will output exactly that, but note the %c
, %s
and %c
format specifiers, which instruct printf(3)
to print a character, followed by a string, followed by another character in that place, which are respectively the 2nd, 3rd and 4th arguments.
The characters, as we saw, are both "
, and the string is s
again (the same string). So the program output is:
char *s = "X"; main(){printf(s,34,s,34);}
Where X
is the string s
in the program. So we get this as output:
char *s = "char *s = %c%s%c; main(){printf(s,34,s,34);}"; main(){printf(s,34,s,34);}
Which, interestingly, is the program source itself.