How to find string element in array regardless of upper or lower case

Question

I want to display alert if myString is present in myArray:

var myString = "A"
var myArray = [A]
if contains(self.arrayGroup, self.txtGroupName.text) {
   let alert = UIAlertView()
        alert.title = "Sorry :("
        alert.message = "Duplicate Name"
        alert.addButtonWithTitle("OK")
        alert.show()
}

But if the myString is in opposite case, the alert is not showing :(

var myStr = "As"
var myArr = [AS]
if contains(self.arrayGroup, self.txtGroupName.text) {
   let alert = UIAlertView()
        alert.title = "Sorry :("
        alert.message = "Duplicate Name"
        alert.addButtonWithTitle("OK")
        alert.show()
}

How can I find myString in myArray ignoring case?

Answer 1

I am guessing what you are looking for is something like the following:

let search = "b"
let arrayToSearch = ["A", "B", "C"]
let searchResult = arrayToSearch.filter() { $0.caseInsensitiveCompare(search) == NSComparisonResult.OrderedSame }
if searchResult.count != 0 {
    print("'\(search)' matched to '\(searchResult[0])'")
} else {
    print("'\(search)'not found")
}

which will output

'b' matched to 'B'