I know that I can reset the indices like so
df.reset_index(inplace=True)
but this will start the index from 0
. I want to start it from 1
. How do I do that without creating any extra columns and by keeping the index/reset_index functionality and options? I do not want to create a new dataframe, so inplace=True
should still apply.
Just assign directly a new index array:
df.index = np.arange(1, len(df)+1)
Or if the index is already 0 based, just:
df.index += 1
Example:
In [151]:
df = pd.DataFrame({'a': np.random.randn(5)})
df
Out[151]:
a
0 0.443638
1 0.037882
2 -0.210275
3 -0.344092
4 0.997045
In [152]:
df.index = np.arange(1, len(df)+1)
df
Out[152]:
a
1 0.443638
2 0.037882
3 -0.210275
4 -0.344092
5 0.997045
TIMINGS
For some reason I can't take timings on reset_index
but the following are timings on a 100,000 row df:
In [160]:
%timeit df.index = df.index + 1
The slowest run took 6.45 times longer than the fastest. This could mean that an intermediate result is being cached
10000 loops, best of 3: 107 µs per loop
In [161]:
%timeit df.index = np.arange(1, len(df)+1)
10000 loops, best of 3: 154 µs per loop
So without the timing for reset_index
I can't say definitively, however it looks like just adding 1 to each index value will be faster if the index is already 0
based