What is the correct way to initialize a variable in C++

Question

I have the following code :

bool c (a == b);

and

bool c {a == b};

where a and b are some variables of same type.

I want to know that, what is the difference in above two initializations and which one should be preferred in what conditions ? Any kind of help will be appreciated.

Answer 1

Both forms are direct initialization.

Using curly braces {} for initialization checks for narrowing conversions and generates an error if such a conversion happens. Unlike (). (gcc issues a warning by default and needs -Werror=narrowing compiler option to generate an error when narrowing occurs.)

Another use of curly braces {} is for uniform initialization: initialize both types with and without constructors using the same syntax, e.g.:

template<class T, class... Args>
T create(Args&&... args) {
    T value{std::forward<Args>(args)...}; // <--- uniform initialization + perfect forwarding
    return value;
}

struct X { int a, b; };
struct Y { Y(int, int, int); };

int main() {
    auto x = create<X>(1, 2);    // POD
    auto y = create<Y>(1, 2, 3); // A class with a constructor.
    auto z = create<int>(1);     // built-in type
}

The only drawback of using curly braces {} for initialization is its interaction with auto keyword. auto deduces {} as std::initializer_list, which is a known issue, see "Auto and braced-init-lists".