PHP preg_match two values how to check with || operator

Question

I need to check if string contains F: # { blabla } or # F: { blabla } how to do that with preg_match? I try with this code but it does not run code when i add # before letter F:

if (preg_match('/F: ([A-za-z0-9]+) ([A-za-z0-9]+)( # (\{.*?\})){0,1}/', $line, $match) || preg_match('/# F: ([A-za-z0-9]+) ([A-za-z0-9]+)( # (\{.*?\})){0,1}/', $line, $match)) {
    echo 'STRING Contains F: and # F:';
}

Here is example:

<?php
$line = 'F: bbb bbb # { startdate=2015-08-10 | enddate=2015-11-10 | info=info | dealer=person548 | test=0 | emu=unknown | free=0 }';
/* $line = '# F: bbb bbb # { startdate=2015-08-10 | enddate=2015-11-10 | info=info | dealer=person548 | test=0 | emu=unknown | free=0 }'; */
if (preg_match('/(# )?F: ([A-za-z0-9]+) ([A-za-z0-9]+)( # (\{.*?\})){0,1}/', $line, $match)) {
    echo 'STRING Contains F: and # F:';
}

Answer 1

The pattern should look like this:

$pattern = '/(F: #|# F:) \{ blabla \}/';

Note the capturing ground (F: #|# F:). It matches one of the patterns separated by the |.

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