Yaml-cpp, old api to new api , operator >>

Question

i would like to convert the following sentence, which is in Yaml-cpp old api format to the new api. how to convert doc["Meta"]["type"] >> type to the new API, as operator >> is deleted in the new api. Thanks

Answer 1

Try the following:

typedef std::string MyType; // I believe, that you're retrieving string
MyType x = doc["Meta"]["type"].as<MyType>();