I'm using PHP's preg_match
to help determine the value of a string.
But the code only ever prints 1 or 2.
Why aren't the last two cases of my if
statement ever matched?
$atype = strtolower($userData['user_type']); // let say data is :: company introducer
if ($atype == "individual introducer" || $atype == "individualintroducer" ||
(preg_match('/i/',$atype) AND preg_match('/int/',$atype)) ) {
$atype = 1 ;
} elseif ($atype == "individual investor" || $atype == "individualinvestor" ||
(preg_match('/i/',$atype) AND preg_match('/inv/',$atype)) ) {
$atype = 2;
} elseif ($atype == "company introducer" || $atype == "companyintroducer" ||
(preg_match('/c/',$atype) AND preg_match('/int/',$atype)) ){
$atype = 3;
} elseif ($atype == "company investor" || $atype == "companyinvestor" ||
(preg_match('/c/',$atype) AND preg_match('/inv/',$atype)) ){
$atype = 4;
}
echo $atype;
You need to explain your question in a better way.
But i guess as you say the data assumed is company introducer
.
So it already matches condition for the first if block. For ex:
In company introducer The preg_match will return true.
if($atype == "individual introducer" || $atype == "individualintroducer" || (preg_match('/i/',$atype) AND preg_match('/int/',$atype)) ){
$atype =1 ;
}