powershell get the bigger disk freespace

Question

I can get all my logical drives and the corresponding freespace with this script:

$elements = get-WmiObject Win32_LogicalDisk
$array=@()

foreach ( $drive in $elements ) {
    $freespace = $drive.freespace / (1024*1024*1024)
    $freespace = [math]::round($freespace, 1) 

    $name=$drive.Name
    $d=New-Object PSObject

    $d | Add-Member -Name Drive -MemberType NoteProperty -Value $name
    $d | Add-Member -Name Free_Space -MemberType NoteProperty -Value $freespace 

    $array+=$d

 }

The problem is that I can't figure out how to manipulate my $array to return the name of the drive with the bigger freespace, with measure -Maximum for example

Answer 1

Try this:

$LogicalDisks = get-WmiObject Win32_LogicalDisk

$MostSpace = 0
$MostName = "None"

foreach ( $drive in $LogicalDisks ) {

$FreeSpace = $drive.FreeSpace / (1024*1024*1024)

$FreeSpace = [math]::round($FreeSpace, 1)

if ($FreeSpace -gt $MostSpace) {
  $MostSpace = $FreeSpace
  $MostName = $Drive.Name
  }

}

Write-Host $MostName

It'll put the drive letter into $MostName and then you can do what you want with it.