In a Python function, Is there a way to tell the argument's variable name on the caller side?

I am trying to create a logger function:

def logger(someVariable): 
    # some code that prints the name of someVariable

So when I call the function:

logger(myvarA)        # should output the string 'myvarA'
logger(someobj.varB)  # should output the string 'someobj.varB'
logger(myarr[3])      # should (probably) output 'myarr[3]'

Not sure if all or even any of these cases are possible? The use case for this is to have a simple function in iPython Notebook to log any variables for their values without having to type something like below:

logger(myVarA,'myVarA')
logger(myarr[i],'myarr[{}]'.format(i))

Solution

The inspect module (https://docs.python.org/3/library/inspect.html#inspect.getframeinfo) will also give you the code context. You simply need to parse that to get the text of what was passed. With only a single variable, it's pretty easy to do. Here's a sample.

import inspect
import re

def handle_nested_parens(v):
   parens = 0
   output = ""
   for c in v:
       if c == ")":
           parens = parens - 1
           if parens < 0:
               return output
       output += c
       if c == "(":
           parens = parens + 1
   return output

def logger(v):
   currentframe = inspect.currentframe()
   code_context = inspect.getouterframes(currentframe,1)[1][4][0]
   variable = handle_nested_parens(re.sub(r".*logger\((.*)",r"\1", code_context))
   print("{0} => {1}".format(variable, v))


def testing(a):
   return(a)

def submain(a):
   ab = (1, 2, a)
   logger(testing(ab))
   return 15

def main():
   xyz = "hello"
   logger(xyz)
   logger(submain(xyz))


if __name__ == '__main__':
    a = 5
    logger(a)
    main()

It outputs

a => 5
xyz => hello
testing(ab) => (1, 2, 'hello')
submain(xyz) => 15